Question

There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

Answer 1

There are four men and six women on the city council.
As one council member is to be selected for a committee at random, the sample space contains 10 (4 + 6) elements.
Let A be the event in which the selected council member is a woman.
Accordingly, n(A) = 6
$∴(P)(A)=\frac{\text{Number of outcomes favourable to A}}{\text{Total number of possible outcomes}}=n(A)/n(S)=\frac{6}{10}=\frac{3}{5}.$