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Question: There are four forces acting at a point P produced by strings as shown in figure, which is at rest. ...

There are four forces acting at a point P produced by strings as shown in figure, which is at rest. The forces F1{F_1} and F2{F_2} are:

A. 12N,32N\dfrac{1}{{\sqrt 2 }}N,\dfrac{3}{{\sqrt 2 }}\,N
B. 32N,12N\dfrac{3}{{\sqrt 2 }}N,\dfrac{1}{{\sqrt 2 }}\,N
C. 12N,12N\dfrac{1}{{\sqrt 2 }}N,\dfrac{1}{{\sqrt 2 }}\,N
D. 32N,32N\dfrac{3}{{\sqrt 2 }}N,\dfrac{3}{{\sqrt 2 }}\,N

Explanation

Solution

When a body is at rest according to Newton’s law the net force acting on the body is zero. Since, Newton’s first law states that if a body is at rest or moving with uniform velocity the body will be at rest or will keep moving with uniform speed or velocity if no external force is applied to it.

Formula used:
The net force acting on the body is given by Newton’s second law as,
F=maF = ma
Where FF is the force acting on the body mm is the mass of the body and aa is the acceleration of the body.
The net force acting on a body at equilibrium, FNet=0{F_{Net}} = 0.

Complete step by step answer:
We have given here from the diagram four forces being applied to a body. Now, to find the value of the forces F1{F_1} and F2{F_2}we have to find the component of the forces 1N1\,Nand 2N2\,Nalong the unknown forces.

So, the components of 1N1Nalong the X-axis and Y-axis are 1Nsin451\,N\sin {45^ \circ } and 1Ncos451\,N\cos {45^ \circ } respectively. Now components of 2N2\,N along the negative X-axis and Y-axis are 2Nsin452\,N\sin {45^ \circ } and 2Ncos452\,N\cos {45^ \circ }respectively. Now, to keep the body at rest all components of force acting along both the axes must be equal.HEcne, we can write for X-component,
F12sin45+1sin45=0{F_1} - 2\sin {45^ \circ } + 1\sin {45^ \circ } = 0
F1212+12=0\Rightarrow {F_1} - 2\dfrac{1}{{\sqrt 2 }} + \dfrac{1}{{\sqrt 2 }} = 0
F1=12\Rightarrow {F_1} = \dfrac{1}{{\sqrt 2 }}
For, y-component we can write,
F22cos451cos45=0{F_2} - 2\cos {45^ \circ } - 1\cos {45^ \circ } = 0
F221212=0\Rightarrow {F_2} - 2\dfrac{1}{{\sqrt 2 }} - \dfrac{1}{{\sqrt 2 }} = 0
F2=32\therefore {F_2} = \dfrac{3}{{\sqrt 2 }}
Hence, the value of F1{F_1}is 12N\dfrac{1}{{\sqrt 2 }}N and the value ofF2{F_2} is 32N\dfrac{3}{{\sqrt 2 }}N.

Hence, option A is the correct answer.

Note: To solve this type of problem remember that the net force at equilibrium is always zero and always from the given forces divide each force into components and equate them to find the value of the unknown forces.