Question
Question: There are 4 numbers. The HCF of each pair is 7 and the LCM of all the numbers is 1470. What is the p...
There are 4 numbers. The HCF of each pair is 7 and the LCM of all the numbers is 1470. What is the product of the 4 numbers?
A.504210
B.502410
C.504120
D.501420
Solution
Hint: Here, we will use the formula to find the LCM of the four numbers without taking the highest common factor of the four numbers equals to the product of the four numbers and HCF, that is, LCM=Product of four numbers×HCF.
Apply this formula, and then use the given conditions to find the required value.
Complete step by step Answer :
Given that the HCF of each pair is 7 and the LCM of all the four numbers is 1470.
Let us assume that the four numbers are 7a, 7b, 7c and 7d.
We know that the formula to find the value of LCM of the four numbers without taking the highest common factor of the four numbers is equals to the product of the four numbers and HCF, that is, LCM=Product of four numbers×HCF.
Substituting the values of HCF, LCM and the four numbers without HCF in the above formula for finding the LCM, we get
⇒1470=abcd×7
Dividing the above equation by 7 on each of the sides, we get
⇒71470=7abcd×7 ⇒210=abcd ⇒abcd=210We will now find the product of the four numbers.
Product of the numbers=7a×7b×7c×7d =74×abcdSubstituting the above value of abcd in the above equation, we get
⇒74×210 ⇒504210Thus, the product of the four numbers is 504210.
Hence, option C will be correct.
Note: In this question, we have to use the formula of the product of four numbers without taking the highest common factor and HCF is equals to LCM. Then use the given conditions and values given in the question, and substitute the values of HCF and LCM in the given formula for LCM, to find the required value. Also, we are supposed to write the values properly to avoid any miscalculation.