Question
Question: There are 10 persons named A, B, .....J. We have the capacity to accommodate only 5. In how many way...
There are 10 persons named A, B, .....J. We have the capacity to accommodate only 5. In how many ways can we arrange them in a line if A is must and G and H must not be included in the team of 5
A
8P5
B
7P5
C
7C3(4!)
D
7C3(5!)
Answer
7C3(5!)
Explanation
Solution
Out of 10 persons, A is in and G and H are out of the team, so we have to select 4 more from 7 remaining. This can be done in 7C4 ways. These 5 persons can be arranged in a line is 5! Ways. Hence the number of possible arrangements is 7C4. 5! = 7C3. (5!)