The(\left( \frac{\lbrack x\rbrack}{{ x}} \right)) equals – | MATH - LIMITS | SolveeIt

The $\left( \frac{\lbrack x\rbrack}{\{ x\}} \right)$ equals –

$\left( \frac{x^{2}}{\sqrt{1 + x^{2}}} \right)$

$\sqrt{4 - x}$

Answer

$\sqrt{4 - x}$

Explanation

= $\lim _ { x \rightarrow \infty } \left\{ \frac { \frac { 16 x ( x + 1 ) ( 2 x + 1 ) } { 6 } - 12 x ( x + 1 ) + 9 x } { 1 - x ^ { 3 } } \right.$

= – $\frac { 32 } { 6 }$ + 2 = $- \frac { 10 } { 3 }$ .

Question: The\(\left( \frac{\lbrack x\rbrack}{\{ x\}} \right)\) equals –...