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Question: The Young's modulus of the material of a wire is \(6 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m }...

The Young's modulus of the material of a wire is 6×1012 N/m26 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 } and there is no transverse strain in it, then its modulus of rigidity will be

A

3×1012 N/m23 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 }

B

2×1012 N/m22 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 }

C

1012 N/m210 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 }

D

None of the above

Answer

3×1012 N/m23 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 }

Explanation

Solution

Y=2η(1+σ)Y = 2 \eta ( 1 + \sigma )

For no transverse strain

(σ = 0)

Y=2ηη=Y2=3×1012 N/m2Y = 2 \eta \Rightarrow \eta = \frac { Y } { 2 } = 3 \times 10 ^ { 12 } \mathrm {~N} / \mathrm { m } ^ { 2 }