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Question: The yield of \(2N_{2}O_{(g)}\)in the the reaction \(7.4 \times 10^{11}Lmol^{- 1}\) \(8715 \times 10^...

The yield of 2N2O(g)2N_{2}O_{(g)}in the the reaction 7.4×1011Lmol−17.4 \times 10^{11}Lmol^{- 1} 8715×1010Lmol−18715 \times 10^{10}Lmol^{- 1} 0.08Lmol−10.08Lmol^{- 1} is affected by

A

Change in pressure and temperature

B

Change in temperature and concentration of O3O_{3}

C

Change in pressure and concentration of O3O_{3}

D

Change in pressure, temperature and concentration of NO2(g)+O2(g)NO_{2(g)} + O_{2(g)}

Answer

Change in pressure, temperature and concentration of NO2(g)+O2(g)NO_{2(g)} + O_{2(g)}

Explanation

Solution

: N2+3H2N_{2} + 3H_{2} 2NH3,ΔH=−22.08kcal2NH_{3},\Delta H = - 22.08kcal

The reaction is exothermic accompanied with decrease in number of moles. So, the equilibrium is affected by temperature, pressure and concentration.