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Question

Physics Question on Motion in a plane

The (x,y,z)(x, y, z) coordinates of two points AA and BB are given respectively as (0,3,1)(0, 3,-1) and (2,6,4)(-2, 6, 4). The displacement vector form AA to BB may be given by:

A

2i^+6j+4k^-2 \hat{i}+6 j+4 \hat{k}

B

2i^+3j+3k^-2 \hat{i}+3 j+3 \hat{k}

C

2i^+3j+5k^-2 \hat{i}+3 j+5 \hat{k}

D

2i^3j5k^2 \hat{i} - 3 j - 5 \hat{k}

Answer

2i^+3j+5k^-2 \hat{i}+3 j+5 \hat{k}

Explanation

Solution

The correct option is(C): =2i^+3j^+5k^.=-2 \hat{ i }+3 \hat{ j }+5 \hat{ k }.

The displacement vector from
A(0,3,1) to B(2,6,4)A \equiv(0,3,-1) \text { to } B \equiv(-2,6,4) is
=(2i^+6j^+4k^)(3j^k^)=(-2 \hat{ i }+6 \hat{ j }+4 \hat{ k })-(3 \hat{ j }-\hat{ k })
=2i^+3j^+5k^=-2 \hat{ i }+3 \hat{ j }+5 \hat{ k }