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Question

Physics Question on Acceleration

The x and y coordinates of the particle at any time are x=5t2t2x = 5t - 2t^2 and y=10ty = 10t respectively, where xx and yy are in meters and t in seconds. The acceleration of the particle at t=2st = 2s is :

A

5m/s25 m/s^2

B

4ms2-4 \, ms^2

C

8ms2 -8 \, ms^2

D

0

Answer

4ms2-4 \, ms^2

Explanation

Solution

x=5t2t2y=10tx=5 t-2 t^{2} \,\,\, y=10 t
dxdt=54tdydt=10\frac{d x}{d t}=5-4 t \,\,\, \frac{d y}{d t}=10
vx=54tvy=10v_{x}=5-4 t \,\,\, v_{y}=10
dvdtx=4dvdty=10\frac{d v}{d t} x=-4 \,\,\, \frac{d v}{d t} y=10
ax=4ay=0a_{x}=-4\,\,\, a_{y}=0
Acceleration of particle at t=2st=2 s is =4m/s2=-4 m / s ^{2}