Question

The wrong statement regarding transition metals among the following is :

• A. 4s electrons penetrate towards the nucleus more than 3d electrons
• B. Atomic radii of transition metals increase rapidly with increase in atomic number because of poor shielding of nuclear attraction by (n – 1)d electrons
• C. Second and third transition series elements have nearly the same size
• D. Their densities are higher and densities of the 5d series elements are higher than those of 4d series elements.

Answer 1

Answer: (B)

Atomic radii of transition metals increase rapidly with increase in atomic number because of poor shielding of nuclear attraction by (n – 1)d electrons

Answer 2

(1) The order of penetration of the electrons present in different sub-shells of same energy level is s > p > d > f.

(2) The decrease in size is small after mid way. In the beginning, the atomic radius decreases with the increase in nuclear charge (as atomic number increases), where as the shielding effect of d-electrons is small. After mid way as the electrons enters the last but one shell, the added d-electron shields the outer most electrons. Hence with the increase in the d-electrons screening effect increases. This counter balances the increased nuclear charge. As a result, the atomic radii remain practically same after chromium.

(3) The filling of 4f before 5d orbital results in a regular decrease in atomic radii called

Lanthanoid contraction which essentially compensates for the expected increase in atomic size with increasing atomic number. The net result of the lanthanoid contraction is that the second and the third d series exhibit similar radii (e.g., Zr 160 pm, Hf 159 pm).

(4) In transition elements, the atomic volumes are large because the increased nuclear charge is poorly screened and so attracts all the electrons more strongly. In addition, the extra electrons added occupy inner orbitals. Consequently the densities of the transition metals are high. The densities of the second row are high and third row values are even higher because of lanthanoid contraction.