Solveeit Logo
Login

Question

Question: The work function of caesium is 2.14eV. The threshold frequency of cesium is :...

The work function of caesium is 2.14eV. The threshold frequency of cesium is :

A

5.16×1019 Hz5.16 \times 10 ^ { 19 } \mathrm {~Hz}

B

5.16×1016 Hz5.16 \times 10 ^ { 16 } \mathrm {~Hz}

C

5.16×1018 Hz5.16 \times 10 ^ { 18 } \mathrm {~Hz}

D

5.16×1014 Hz5.16 \times 10 ^ { 14 } \mathrm {~Hz}

Answer

5.16×1014 Hz5.16 \times 10 ^ { 14 } \mathrm {~Hz}

Explanation

Solution

: Here ϕ0=2.14eV\phi _ { 0 } = 2.14 \mathrm { eV }

Work function ϕ0=hv0\phi _ { 0 } = h v _ { 0 }

Where is the threshold frequency

v0=ϕ0h=2.14×1.6×10−196.63×1034=5.16×1014 Hzv _ { 0 } = \frac { \phi _ { 0 } } { h } = \frac { 2.14 \times 1.6 \times 10 ^ { - 19 } } { 6.63 \times 10 ^ { 34 } } = 5.16 \times 10 ^ { 14 } \mathrm {~Hz}