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Question

Physics Question on Electrostatic potential

The work done in placing a charge of 8??10−188 ??10^{-18} coulomb on a condenser of capacity 100 micro-farad is

A

16??10−3216 ??10^{-32} joule

B

3.2??10−263.2 ??10^{-26} joule

C

4??10−104 ??10^{-10} joule

D

32??10−3232 ??10^{-32} joule

Answer

32??10−3232 ??10^{-32} joule

Explanation

Solution

Required work done is w=12Q2C2w=\frac{1}{2} \frac{Q^{2}}{C^{2}} =12×(8×10−18)210−4=32×10−32 J=\frac{1}{2}\times\frac{\left(8\times10^{-18}\right)^{2}}{10^{-4}}=32\times10^{-32}\,J