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Question

Chemistry Question on Gas laws

The work done during reversible isothermal expansion of one mole of hydrogen gas at 25oC from a pressure of 20 atm to 10 atm is:
(Given R = 2.0 cal K-1 mol-1)

A

0 calorie

B

-413.14 calories

C

413.14 calories

D

100 calories

Answer

-413.14 calories

Explanation

Solution

1. For isothermal expansion, work done is calculated as:

W=nRTlnP2P1W = -nRT \ln \frac{P_2}{P_1}

2. Substituting the given values:

W=(1)×(2.0)×(298)×ln(1020)W = -(1) \times (2.0) \times (298) \times \ln \left(\frac{10}{20}\right)

3. Simplify:

W=596×ln(0.5)=596×(0.693)413.14 caloriesW = -596 \times \ln(0.5) = -596 \times (-0.693) \approx -413.14 \text{ calories}.