Question
Question: The work done by the frictional force on a pencil in drawing a complete circle of radius \(r = \dfr...
The work done by the frictional force on a pencil in drawing a complete circle of
radius r=π1 metre on the surface by a pencil of negligible mass with a normal
pressing force N=5N(μ=0.5)
(A) +4J
(B) −3J
(C) −2J
(D) −5J
Solution
In order to solve the problem we need to know about what is work done by frictional force and knowledge about normal force , direction of normal force , direction of frictional force.
Work done by frictional force is
dw
$$$$dw=Fk.dl
Here Fk is the frictional force opposite to the applied force
Due to opposite in direction we can say that
dw=−Fk.dl
Given:
a pencil in drawing a complete circle of radius r=π1 metre on the surface by a pencil of negligible mass with a normal pressing force N=5N
and μk=0.5(coefficient of kinetic friction)
To find the work done by the frictional force on a pencil
Complete step by step solution:
As per the given question first, we will draw the diagram as per the given situation,
Let the frictional force applied be Fk
Fk acts tangentially opposite to the motion of the pencil.
For elementary displacement dl
The work done by Fkis dw
dw=Fk.dl=−FK.dl
Integrating on both side, we get
∫0Wdw=−∫02πrFK.dl
∫0Wdw=−μkN∫02πrdl as we know (FK=μkN)
W=−μkN2πr
Put value of μk,r,N
W=−0.5×5×2×π×π1
W=−5J is the work done by the frictional force on a pencil in drawing a complete circle.
So the correct answer is (d).
Note: We see friction in our day to day activities. Following are the ten examples of friction in daily life:
1. Walking
2. Writing
3. Scating
4. Lighting a matchstick
5. Driving of the vehicle on a surface
6. Applications of breaks in the vehicle to stop it
7. Flight of aeroplanes
8. Drilling a nail into the wall
9. The dusting of the carpet by beating it with a stick
10. Sliding on a garden slide