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Question

Physics Question on Magnetic Field

The work done by an uniform magnetic field, on a moving charge is

A

zero because F\vec{F} acts parallel to v\vec{v}

B

positive because F\vec{F} acts perpendicular to v\vec{v}

C

zero because F\vec{F} acts perpendicular to v\vec{v}

D

negative because F\vec{F} acts parallel to v\vec{v}

Answer

zero because F\vec{F} acts perpendicular to v\vec{v}

Explanation

Solution

Force on moving charge while moving in magnetic field is; F=q(v×B)\vec{F}=q\left(\vec{v}\times\vec{B} \right) where F\vec{F} is perpendicular to v\vec{v}
Work done/sec =F,v=Fvcos90=0=\vec{F},\vec{v}=Fv\,cos\,90�=0