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Physics Question on work, energy and power

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m20\,m is

A

212.5 J

B

400 J

C

175 J

D

225 J

Answer

212.5 J

Explanation

Solution

Work done is equal to the area under the graph.
From 0−5:W1=37.5 JFrom \, 0-5: W _{1}=37.5 \,J
From 5−15:W2=100 JFrom \, 5-15: W _{2}=100\, J
 From 15−20:W3=75 J\text { From } 15-20: W _{3}=75\, J
Total work done =37.5+100+75=212.5 J= 3 7 . 5 + 1 0 0 + 7 5 = 2 1 2 . 5\, J