Question

The weight of oxalic acid that will be required to prepare a $1000\, mL$ $\left(\frac{N}{20}\right)$ solution is

• A. 126 / 100 g
• B. 63 / 40 g
• C. 63 / 20 g
• D. 126 / 20 g

Answer 1

Answer: (C)

63 / 20 g

Answer 2

$w=\frac{N E V}{1000}$
$=\frac{1}{20} \times \frac{63 \times 1000}{1000}=\frac{63}{20} g$