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Question

Chemistry Question on Some basic concepts of chemistry

The weight of one molecule of a compound C60H122C _{60} H _{122} is

A

1.2×1020g1.2 \times 10^{-20} \,g

B

5.025×1023g5.025 \times 10^{23} \,g

C

1.4×1021g1.4 \times 10^{-21} \,g

D

6.023×1023g6.023 \times 10^{23}\, g

Answer

1.4×1021g1.4 \times 10^{-21} \,g

Explanation

Solution

The molecular weight of C60H122=60×12+122=720+122=842C _{60} H _{122}=60 \times 12+122=720+122=842 The weight of one molecule of C60H122C _{60} H _{122} == molecular wt. of compound/Avogadro number =8426.023×1023=\frac{842}{6.023 \times 10^{23}} =1.4×1021g=1.4 \times 10^{-21}\, g