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Question

Physics Question on Gravitation

The weight of an object at earth's surface is 700gwt700\, g\, wt. What will be its weight at the surface of a planet whose radius is 1/21 / 2 and mass is 1/71 / 7 of that of the earth ?

A

200 g wt.

B

400 g wt.

C

50 g wt.

D

300 g wt.

Answer

400 g wt.

Explanation

Solution

Weight at earth's surface w=mgw=m g Acceleration due to gravity at earth's surface g=GMcRe2g=\frac{G M_{c}}{R_{e}^{2}} For planet, g=GMR2=GMc/7(Re/2)2g'=\frac{G M}{R^{2}}=\frac{G M_{c} / 7}{\left(R_{e} / 2\right)^{2}} =47GmeRe2=47g=\frac{4}{7} \frac{G m_{e}}{R_{e}^{2}}=\frac{4}{7} g \therefore Weight at the surface of planet =mg=m g' =m(4g7)=m\left(\frac{4 g}{7}\right) =47mg=47×700=\frac{4}{7} m g=\frac{4}{7} \times 700 =400gwt=400\, g\, wt