Question

The weight of a person is 60 kg. If he gets 10⁵ calories heat through food and the efficiency of his body is 28%, then upto how much height he can climb (approximately)

• A. 100 m
• B. 200 m
• C. 400 m
• D. 1000 m

Answer 1

Answer: (B)

200 m

Answer 2

Suppose person climbs upto height h, then by using

$W = JH$ ⇒ $mgh = JQ$

⇒ $60 \times 9.8 \times h = 4.2 \times \left( 10^{5} \times \frac{28}{100} \right)$ ⇒ $h = 200m$