Question
Question: The weight of a person is 60 kg. If he gets \({{10}^{5}}\) calories heat through food and the effici...
The weight of a person is 60 kg. If he gets 105 calories heat through food and the efficiency of his body is 28% then upto how much height he can climb when he uses the entire energy gained in climbing.
A. 100m
B. 200m
C. 400m
D. 1000m
Solution
To solve this question first convert the energy from calorie to joule. Then find the energy consumed by the man. Let the height the man climbs is h. find the potential energy needed to climb this height. Equate this energy with the obtained energy to find the required answer.
Complete step by step answer:
We have a person whose weight m=60kg
He gets 105 calories heat through food.
Converting this heat energy from calories to the unit of joule. We get that
H=105calories=4.2×105joule
Now, the efficiency of his body is 28%.
So, the energy obtained by the man is,
E=10028×4.2×105jouleE=1.176×105joule
Now, let the man climb up to a height of h.
So, the potential energy of the man at the height of h will be, PE=mgh
Where, g is the acceleration due to gravity.
Again, the potential energy is equal to the energy lost by the while climbing the height h.
So, the potential energy will be equal to the entire energy obtained by the man.
So, we can write,