Question
Question: The weak acid, HA has a \({{K}_{a}}\) of \(1\times {{10}^{-5}}\) . If 0.1 mol of this acid is dissol...
The weak acid, HA has a Ka of 1×10−5 . If 0.1 mol of this acid is dissolved in
one litre of water, the percentage of acid dissociated at equilibrium is closest to:
a.) 1%
b.) 99.9%
c.) 0.1%
d.) 99%
Solution
An acid is a substance which dissociates in aqueous solution. We can write the equation of dissociation as- HA=H++A− .
For calculating the percentage of an acid dissociated you can divide the mass of dissociated ions by the total mass of dissociated and undissociated species and then multiply by 100 percent and thus you will get the required percentage.
Complete step by step answer:
The acid dissociation constant (Ka) or the ionization constant is the measure of the strength of acid in a solution.
The dissociation constant can be given by-
Ka=[HA][H+][A−]
Now in the given question, the initial concentration of HA is 0.1 mol/L, suppose the initial concentration of H+ and A− is x. Therefore, we can write that-