Question

The wavelength of X-rays which gives a diffraction angle, 2 $\theta$, equal to $16.80^{\circ}$ for a first order diffraction for a crystal with interplanar distance 0.200 nm, is (given sin $8.4^{\circ}$ and 0.146)

• A. 0.0584 nm
• B. 0.1168 nm
• C. 0.0292 nm
• D. 0.2336 nm

Answer 1

Answer: (A)

0.0584 nm

Answer 2

$n \lambda = 2 \, d \, \sin \, \theta, 1 \times \lambda = 2 \times 0.200 \, \sin \, 8.4$ or $\lambda = 2 \times 0.2 \times 0.146 = 0.0584 \, nm$.