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Question

Question: The wavelength of series limit of Lyman series is-...

The wavelength of series limit of Lyman series is-

A

B

R

C

1/n

D

14R\frac{1}{4R}

Answer

1/n

Explanation

Solution

1λ\frac{1}{\lambda} = RZ2 (1n121n22)\left( \frac{1}{n_{1}^{2}}–\frac{1}{n_{2}^{2}} \right)