Question

The wavelength of radiation emitted is l₀ when an electron in Hydrogen atom jumps from the third orbit to second. If in the Hydrogen atom itself, the electron jumps from fourth orbit to second orbit, the wavelength of emitted radiation will be –

• A. $\frac{16}{25}\lambda_{0}$
• B. $\frac{20}{27}\lambda_{0}$
• C. $\frac{27}{20}\lambda_{0}$
• D. $\frac{25}{16}\lambda_{0}$

Answer 1

Answer: (B)

$\frac{20}{27}\lambda_{0}$

Answer 2

$\frac{hc}{\lambda_{0}}$=1.5eV+3.4eV=1.9eV;

$\frac{hc}{\lambda}$=0.85eV+3.4ev=2.55eV

$\frac{\lambda}{\lambda_{0}} = \frac{1.9}{2.55}$ l = $\frac{1.9}{2.55}\lambda_{0} = \frac{20}{27}\lambda_{0}$