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Question: The wavelength of maximum energy released during an atomic explosion was \(2.93 \times 10^{- 10}m\)....

The wavelength of maximum energy released during an atomic explosion was 2.93×1010m2.93 \times 10^{- 10}m. Given that Wien's constant is 2.93×103m2.93 \times 10^{- 3}m–K, the maximum temperature attained must be of the order of

A

10–7 K

B

107 K

C

10–13 K

D

5.86×107K5.86 \times 10^{7}K

Answer

107 K

Explanation

Solution

From Wien's displacement law λmT=b\lambda_{m}T = b

T=bλm=2.93×1032.93×1010=107KT = \frac{b}{\lambda_{m}} = \frac{2.93 \times 10^{- 3}}{2.93 \times 10^{- 10}} = 10^{7}K.