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Question: The wavelength of maximum energy, released during an atomic explosion, was 2.93 ´ 10<sup>-10</sup> m...

The wavelength of maximum energy, released during an atomic explosion, was 2.93 ´ 10-10 m. Given that the Wien's constant is 2.93 ´ 10-3 m K, the maximum temperature attained must be of the order of

A

10-7 K

B

107 K

C

10-13 K

D

5.86 ´ 107 K

Answer

107 K

Explanation

Solution

λmT=b\lambda_{m}T = b2.93×1010×T=2.93×1032.93 \times 10^{- 10} \times T = 2.93 \times 10^{- 3}⇒ T = 107 K