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Question: The wavelength of light emitted from second orbit to first orbits in a hydrogen atom is....

The wavelength of light emitted from second orbit to first orbits in a hydrogen atom is.

A

1.215×10−7m1.215 \times 10^{- 7}m

B

1.215×10−5m1.215 \times 10^{- 5}m

C

1.215×10−4m1.215 \times 10^{- 4}m

D

1.215×10−3m1.215 \times 10^{- 3}m

Answer

1.215×10−7m1.215 \times 10^{- 7}m

Explanation

Solution

Energy radiated

E=10.2eV=10.2×1.6×10−19JE = 10.2eV = 10.2 \times 1.6 \times 10^{- 19}J

⇒ E=hcλE = \frac{hc}{\lambda} ⇒ λ=1.215×10−7m\lambda = 1.215 \times 10^{- 7}m