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Question: The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus wi...

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly

A

1.2 nm

B

1.2×10−3 m1.2 \times 10 ^ { - 3 } \mathrm {~m}

C

1.2×10−6 nm1.2 \times 10 ^ { - 6 } \mathrm {~nm}

D

1.2×101 nm1.2 \times 10 ^ { 1 } \mathrm {~nm}

Answer

1.2×10−3 m1.2 \times 10 ^ { - 3 } \mathrm {~m}

Explanation

Solution

: Here,

c=3×108 ms−1c = 3 \times 10 ^ { 8 } \mathrm {~ms} ^ { - 1 }

∵hc=6.63×10−34×351081.6×10−19≈1240eVnm\because h c = \frac { 6.63 \times 10 ^ { - 34 } \times 3510 ^ { 8 } } { 1.6 \times 10 ^ { - 19 } } \approx 1240 \mathrm { eVnm }

As E=hcλE = \frac { h c } { \lambda }

Or