Question

The wave number of the shortest wave length transition in Balmer series of atomic hydrogen will be :

• A. 4215Å
• B. 1437 Å
• C. 3942 Å
• D. 3647 Å

Answer 1

Answer: (D)

3647 Å

Answer 2

$\frac{1}{\lambda_{shortest}}$= RZ² $\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)$ = 109678 × 1² × $\left( \frac{1}{2^{2}} - \frac{1}{\infty^{2}} \right)$

λ = 3.647 × 10^–5 cm = 3647 Å