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Question

Chemistry Question on Structure of atom

The wave number of the limiting line in Lyman series of hydrogen is 109678 cm1cm^{-1}. The wave number of the limiting line in Balmer series of He+He^{+} would be :

A

54839 cm1cm^{-1}

B

109678 cm1cm^{-1}

C

219356 cm1cm^{-1}

D

438712 cm1cm^{-1}

Answer

109678 cm1cm^{-1}

Explanation

Solution

Series limit of Lyman series, n1=1;n2=n_{1}=1 ; n_{2}=\infty
\therefore wave number is given by -
γˉ=R[1n121n22]\bar{\gamma}=R\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]
[R=109678cm1]\left[\because R=109678 \,cm ^{-1}\right]
γˉ=109678[11212]cm1\Rightarrow \bar{\gamma}=109678\left[\frac{1}{12}-\frac{1}{\infty^{2}}\right] cm ^{-1} .
γˉ=109678[10]cm1\Rightarrow \bar{\gamma}=109678[1-0] cm ^{-1} .
γˉ=109678cm1\Rightarrow \bar{\gamma}=109678\, cm ^{-1} .