Solveeit Logo

Question

Question: The volume V of water passing through a point of a uniform tube during t seconds is related to the c...

The volume V of water passing through a point of a uniform tube during t seconds is related to the cross-sectional area A of the tube and velocity u of water by the relation VAαuβtγV \propto A^{\alpha}u^{\beta}t^{\gamma}, which one of the following will be true

A

α=β=γ\alpha = \beta = \gamma

B

αβ=γ\alpha \neq \beta = \gamma

C

α=βγ\alpha = \beta \neq \gamma

D

αβγ\alpha \neq \beta \neq \gamma

Answer

αβ=γ\alpha \neq \beta = \gamma

Explanation

Solution

Writing dimensions of both sides

[L3]=[L2]α[LT1]β[T]γ[L3T0]=[L2α+βTγβ]\lbrack L^{3}\rbrack = \lbrack L^{2}\rbrack^{\alpha}\lbrack LT^{- 1}\rbrack^{\beta}\lbrack T\rbrack^{\gamma} \Rightarrow \lbrack L^{3}T^{0}\rbrack = \lbrack L^{2\alpha + \beta}T^{\gamma - \beta}\rbrack

By comparing powers of both sides 2α+β=32\alpha + \beta = 3 and γβ=0\gamma - \beta = 0

Which give β=γ\beta = \gamma and α=12(3β)\alpha = \frac{1}{2}(3 - \beta) i.e. αβ=γ\alpha \neq \beta = \gamma.