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Question: The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio ...

The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas to the heat absorbed by it, when it undergoes a change from state A to state B, is?

A.13A.\,\dfrac{1}{3}
B.25B.\,\dfrac{2}{5}
C.27C.\,\dfrac{2}{7}
D.23D.\,\dfrac{2}{3}

Explanation

Solution

This problem is a direct question. We will make use of the specific heat at a constant pressure of monatomic gas and substitute the same value in the equation of heat absorbed. Then we will divide this equation by the equation of the work done in the case of the isobaric process. Thus, we will get the required ratio.

Complete step-by-step solution
From given problem, we have a monatomic gas, so, we have,
CP=52R{{C}_{P}}=\dfrac{5}{2}R
Or we can compute the specific heat at constant pressure as follows.

& {{C}_{P}}=\dfrac{3}{2}R+R \\\ & {{C}_{P}}=\dfrac{5}{2}R \\\ \end{aligned}$$ Now, we will consider the heat absorbed. $$dQ=n{{C}_{p}}dT$$ Substitute the equation of the specific heat at constant pressure expression in the above equation. $$dQ=n\left( \dfrac{5}{2}R \right)dT$$ For an isobaric process, the work done is given as follows. $$\begin{aligned} & dW=P\times dV \\\ & dW=nRdT \\\ \end{aligned}$$ The ratio of work done by the gas to the heat absorbed by it, when it undergoes a change from state A to state B, is $$\begin{aligned} & \text{Ratio}=\dfrac{dW}{dQ} \\\ & \text{Ratio}=\dfrac{nRdT}{n\left( \dfrac{5}{2}R \right)dT} \\\ \end{aligned}$$ $$\therefore $$ The ratio of work done by the gas to the heat absorbed by it, when it undergoes a change from state A to state B is give as follows, $$\text{Ratio}=\dfrac{2}{5}$$ **As the ratio of work done by the gas to the heat absorbed by it, when it undergoes a change from state A to state B be $$\dfrac{2}{5}$$, thus, the option (B) is correct.** **Note:** If we know the formula for computing the excess pressure inside a soap bubble, then, we can solve this problem, otherwise, we need to find the formula first. The derivation for the excess pressure inside a soap bubble is discussed above to make the student know how we obtain the formula for computing the excess pressure inside a soap bubble.