Question

The volume V and depth x of water in a vessl are connected by the relation $V = 5x - \frac{x^2}{6}$ and the volume of water is increasing , at the rate of $5 \, cm^3/sec$, when x = 2 cm. The rate at which the depth of water is increasing, is

• A. $\frac{5}{18} cm / \sec$
• B. $\frac{1}{4} cm / \sec$
• C. $\frac{5}{16} cm / \sec$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$V = 5x - \frac{x^{2}}{6} \Rightarrow \frac{dV}{dt} = 5 \frac{dx}{dt} - \frac{x}{3}. \frac{dx}{dt}$ $\Rightarrow \frac{dx}{dt} = \frac{\frac{dV}{dt}}{\left(5 - \frac{x}{3}\right)}$ $\Rightarrow \left(\frac{dx}{dt}\right)_{x=2} = \frac{5}{5- \frac{2}{3}} = \frac{15}{13} cm / \sec$