Question

The volume of water to be added to 100 $cm^3$ of 0.5 $NH_2SO_4$ to get decinormal concentration is

• A. 400 $cm^3$
• B. 500 $cm^3$
• C. 450 $cm^3$
• D. 100 $cm^3$

Answer 1

Answer: (A)

400 $cm^3$

Answer 2

$N_1 V_1 = N_2V_2$ $0.5\,N \times 100\,cm^3\,=\,0.1\,N\times V_1$ $V_1 = 500\,cm^3$ Water to be added = $(500-100) cm^3 = 400 cm^3$