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Question: The volume of vessel A is twice the volume of another vessel B, and both of them are filed with the ...

The volume of vessel A is twice the volume of another vessel B, and both of them are filed with the same gas. If the gas in A is at twice the temperature and twice the pressure in comparison to the gas in B, then the ratio of the gas molecules in A to that of B is

A

12\frac{1}{2}

B

21\frac{2}{1}

C

32\frac{3}{2}

D

23\frac{2}{3}

Answer

21\frac{2}{1}

Explanation

Solution

PV = Nrt

nB=PVRTandnA=2P×2VR×2T\therefore n_{B} = \frac{PV}{RT}andn_{A} = \frac{2P \times 2V}{R \times 2T}

or nA=2PVRTn_{A} = \frac{2PV}{RT}

nAnB=21\therefore\frac{n_{A}}{n_{B}} = \frac{2}{1}