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Question

Mathematics Question on Vector Algebra

The volume of the tetrahedron formed by the points (1,1,1),(2,1,3),(3,2,2)(1, 1, 1 ), (2, 1, 3), (3, 2, 2) and (3,3,4)(3, 3, 4) in cubic units is

A

44687

B

44717

C

5

D

44595

Answer

44687

Explanation

Solution

Let A(1,1,1),B(2,1,3),C(3,2,2)A(1, 1, 1), B(2, 1, 3), C(3, 2, 2) and D(3,3,4)D(3,3, 4)
ABˉ=(21,11,31)=(1,0,2)\bar{AB} = (2-1, 1-1, 3 -1) = (1, 0, 2)
ACˉ=(31,21,21)=(2,1,1)\bar{AC} =(3-1, 2-1, 2-1) =(2,1,1)
ADˉ=(31,31,41)=(2,2,3)\bar{AD} = (3-1, 3 -1, 4 -1) = (2, 2, 3)
V=16[uˉ,vˉ,wˉ]V = \frac{1}{6} |[\bar{u}, \bar{v}, \bar{w}]|
[uˉ,vˉ,wˉ]102 211 223=1(32)+2(42)[\bar{u}, \bar{v}, \bar{w}]\begin{vmatrix}1&0&2\\\ 2&1&1\\\ 2&2&3\end{vmatrix}=1\left(3-2\right)+2\left(4-2\right)
=1+2(2)=5V=16.5=56= 1+2\left(2\right)=5 \Rightarrow V =\frac{1}{6}.5=\frac{5}{6} cubic units