Question

The volume of hydrogen at NTP displaced by that.amount of current which displaced 1 .08 g of Ag(equivalent weight of Ag = 108) will be

• A. 1120 cc
• B. 11.2 cc
• C. 112 cc
• D. 11200 cc

Answer 1

Answer: (C)

112 cc

Answer 2

$g$ e of hydrogen $= g$ e of $Ag$ $\frac{W}{1} = \frac{1.08}{108} = 0.01\,g$ $2g\, H_2$ has volume at $N.T.P. = 22400 \,cc$. $0.01\,g\, H_2$ has volume at $N.T.P = \frac{22400}{2} \times 0.01$ $= 112\,cc$.