Question

The volume of gases evolved when dil ${{H}_{2}}S{{o}_{4}}$ electrolyzed using $2F$ at $STP$ is
(A) $22.4L$
(B) $11.2L$
(C) $33.6L$
(D) $44.8L$

Answer 1

Electrolysis :- The process of a that causing chemical reaction by passing an current through a liquid solution of substance. As a result it breaks down into its respective anion and cation.

Complete Step By Step Solution
Electrolysis of dil ${{H}_{2}}S{{o}_{4}}$ :- Dilate sulphuric acid consists of water molecules. The ion present in dil ${{H}_{2}}S{{o}_{4}}$ are ${{H}_{2}}^{{{+}_{{}}}}OH$ ion from water and ${{H}^{+}}$ and ion from the sulphuric acid . The positive ions attracted towards the cathode whereas negative ions towards the anode.
Reaction takes place cathode
$2{{H}^{+}}+2{{e}^{-}}\to {{H}_{2}}$
At Anode
$4o{{H}^{-}}\to {{o}_{2}}+2{{H}_{2}}o+4{{e}^{-}}$
2 moles of electrons gives us one mole of ${{o}_{2}}2{{H}_{2}}$ when $2F$ electricity gives 2 moles of gases .
Mole of gases at $STP$ is equivalent to = $22.4L$
Mole of gases at $STP$ is equivalent to = $2\times {{22}_{4}}$
= $44.8L$
So, the ‘D’ is the correct option

Note
The knowledge of the electrolysis of dil sulphuric acid must be the knowledge of how much litre of gas consists of $STP$ of 1 mole because all these things helpful to solve the problem.Related to electrolysis of liquid.