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Question: The volume of a gas in a discharge tube is \(1.12\times {{10}^{-7}}\) ml at STP. Then the number of ...

The volume of a gas in a discharge tube is 1.12×1071.12\times {{10}^{-7}} ml at STP. Then the number of molecules of gas in the tube is:
A. 3.01×1043.01\times {{10}^{4}}
B. 3.01×10153.01\times {{10}^{15}}
C. 3.01×10123.01\times {{10}^{12}}
D. 3.01×10163.01\times {{10}^{16}}

Explanation

Solution

At standard temperature and pressure (STP) one mole of gas occupies 22400 ml of volume. At the time of calculation of number of molecules of a gas at STP we should consider the Avogadro number also.
Avogadro number = 6.023×10236.023\times {{10}^{23}} atoms or molecules

Complete Solution :
- In the question it is given that to calculate the number of molecules of a gas present with a volume of 1.12×1071.12\times {{10}^{-7}} ml at STP in a discharge tube.
- We know that one mole of gas occupies 22400 ml of volume.
- Therefore the number of moles in a volume of 1.12×1071.12\times {{10}^{-7}} ml will be calculated as follows.
Number of moles of the gas = 1.12×10722400\dfrac{1.12\times {{10}^{-7}}}{22400}
- We should calculate the number of molecules present in the volume of 1.12×1071.12\times {{10}^{-7}} ml and it is as follows.
- Number of molecules in 1.12×1071.12\times {{10}^{-7}} ml volume of the gas is

& =\frac{1.12\times {{10}^{-7}}}{22400}\times {{N}_{A}} \\\ & =\frac{1.12\times {{10}^{-7}}}{22400}\times 6.023\times {{10}^{23}} \\\ & =3.01\times {{10}^{12}} \\\ \end{aligned}$$ Here ${{N}_{A}}$ = Avogadro number = $6.023\times {{10}^{23}}$ atoms or molecules. \- Therefore the number of molecules in a gas which is present in a discharge tube with a volume of $1.12\times {{10}^{-7}}$ ml is $3.01\times {{10}^{12}}$ . **So, the correct answer is “Option C”.** **Note:** At the time of calculation of the number of molecules for gas we should consider the volume of a one mole of gas at standard temperature and pressure (STP). The volume of one mole of gas at STP is equal to 22400 ml.