Question

The volume of a gas expands by $0.25 \,m ^{3}$ at a constant pressure of $10^{3} \,N / m$. The work done is equal to

• A. 250 watt
• B. 2.5 erg
• C. 250 newton
• D. 250 joule

Answer 1

Answer: (D)

250 joule

Answer 2

Given: Change in volume of a gas $(dV) =0.25\, m ^{3}$ and constant pressure $(P)=10^{3}\, N / m ^{2}$. We know that work done $(W)=P \cdot d V=10^{3} \times 0.25$ $=250$ joule.