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Question

Chemistry Question on Surface Chemistry

The volume of a colloidal particle, VCV_C as compared to the volume of a solute particle in a true solution VSV_S, could be :

A

VcVs103 \frac{V_{c}}{V_{s}} \approx 10^{3}

B

VcVs103 \frac{V_{c}}{V_{s}}\simeq 10^{-3}

C

VcVs1023 \frac{V_{c}}{V_{s}}\simeq 10^{23}

D

VcVs1 \frac{V_{c}}{V_{s}}\simeq 1

Answer

VcVs103 \frac{V_{c}}{V_{s}} \approx 10^{3}

Explanation

Solution

Size of colloidal particles = 1 to 100 nm (say 10 nm) Vc=43πr3=43π(10)3V_{c} = \frac{4}{3}\pi r^{3} = \frac{4}{3}\pi\left(10\right)^{3} Size of true solution particles \approx 1 nm Vs=43π(1)3V_{s} = \frac{4}{3}\pi \left(1\right)^{3} ThusVcVs=103\quad\quad \frac{V_{c}}{V_{s}} = 10^{3}