Solveeit Logo
Login

Question

Chemistry Question on Laws of Chemical Combinations

The volume of 11 mole of any pure gas at standard temperature and pressure is always equal to

A

0.022414 m3 0.022414 \,m^{3}

B

22.414 m3 22.414 \,m^{3}

C

2.2414 m3 2.2414 \,m^{3}

D

0.22414 m3 0.22414 \,m^{3}

Answer

0.022414 m3 0.022414 \,m^{3}

Explanation

Solution

The volume of 1 mole of any pure gas at

standard and pressure (STP) Is equal to 22.414 L22.414 \,L

1 L=10−3 m31\,L =10^{-3}\,m^{3}

∴22.4 L=0.022414 m3\therefore 22.4\,L =0.022414\,m^{3}