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Question: The volume occupied by 88 g of \(CO_{2}\)at \(30^{0}C\)and 1 bar pressure will be...

The volume occupied by 88 g of CO2CO_{2}at 300C30^{0}Cand 1 bar pressure will be

A

5.05L5.05L

B

49.8L49.8L

C

2L

D

55 L

Answer

49.8L49.8L

Explanation

Solution

: w = 88 g, M = 44 g mol−1,mol^{- 1}, T=273+30=303k

P = 1 bar, V = ?

PV = nRT or V=nRTP=wMRTpV = \frac{nRT}{P} = \frac{w}{M}\frac{RT}{p}

V88×0.0821×30344×1=49.8L\frac{88 \times 0.0821 \times 303}{44 \times 1} = 49.8L