Question

The volume occupied by $16\,g$ of oxygen gas at $STP$ is

• A. $22.4\,L$
• B. $44.8\,L$
• C. $11.2\,L$
• D. $5.6\,L$

Answer 1

Answer: (C)

$11.2\,L$

Answer 2

$1$ mole of a gas occupy $= 22.4\, L$ volume at $STP$ therefore, $16 \,g \,O_2$ gas $= 0.5$ mole of $O_2$ gas will occupy $= \frac{0.5\times 22.4}{1} = 11.2 \,L$ at $STP$.