Question

The volume occupied by 1.8 g of water vapour at 374 °C and 1 bar pressure will be :- [Use R = 0.083 bar L $K^{-1}mol^{-1}$]

• A. 96.66 L
• B. 55.87 L
• C. 3.10 L
• D. 5.37 L

Answer 1

Answer: (D)

5.37 L

Answer 2

$PV = nRT$
$n = 1.8/18 = 0.1$mole
$P = 1$ bar
$T = 374 + 273$
$= 647 \,K$
$V = \frac{nRT}{P}$
$= \frac{0.1 \times 0.083 \times 647}{1}$
$= 5.37\,L$