Question

The vertices of the hyperbola are at (-5,-3) and (-5,-1) and the extremities of the conjugate axis are at (-7,-2) and (-3,-2), then the equation of the hyperbola is

• A. $\frac{(y-2)^2}{1}-\frac{(x-5)^2}{4}=1$
• B. $\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1$
• C. $\frac{(x+5)^2}{4}-\frac{(y+2)^2}{1}=1$
• D. $\frac{(x-5)^2}{4}-\frac{(y-2)^2}{1}=1$

Answer 1

Answer: (B)

$\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1$

Answer 2

The correct option is (B) : $\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1$.