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Question

Physics Question on projectile motion

The vertical component of velocity of a projectile at its maximum height (u=u = velocity of projection, θ=\theta = angle of projection) is

A

usinθu \sin \theta

B

ucosθu \cos \theta

C

usinθ\frac{u}{\sin \theta}

D

0

Answer

0

Explanation

Solution

The vertical component of velocity of a projectile at maximum height is zero.