Question

The vertical component of earth’s magnetic field at a place is $\sqrt { 3 }$ times the horizontal component the value of angle of dip at this place is

• A. 30°
• B. 45°
• C. 60°
• D. 90°

Answer 1

Answer: (C)

60°

Answer 2

: As, ,

Also, $\tan \delta = \frac { \mathrm { B } _ { \mathrm { V } } } { \mathrm { B } _ { \mathrm { H } } } = \frac { \sqrt { 3 } \mathrm {~B} _ { \mathrm { H } } } { \mathrm { B } _ { \mathrm { H } } } = \sqrt { 3 }$

Or , $\delta = \tan ^ { - 1 } ( \sqrt { 3 } ) = 60 ^ { \circ }$

Angle of dip, $\delta = 60 ^ { \circ }$