Question

The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be ________× 10-2 cm.

Answer 1

The correct answer is 180
As the zero error is negative, we will add 0.05 cm to the reading
⇒ Corrected reading = 1.7 cm + 5 × 0.1 mm + 0.05 cm
= 180 × 10–2 cm